5-3: 1 SEE ANSWER

Answer: 180 Hz, 360 Hz, and 540 Hz.

Start with the basic equation:

    fn = (n/(2L)) X (the square root of (T/d))

Plug in the numbers given:

    fn = (n/ (2 X 0.7 m)) X (the square root of (52 N/ 0.0082 kg/m))
    fn = (n/1.4m) X (the square root of (63415 m squared/ s squared)
    fn = n X 180 s^-1
    fn = n180 Hz (n = 1, 2, 3,...)

The distance between each harmonic will be 180 Hz. So the first three harmonics will be 180 Hz, 360 Hz, and 540 Hz.

1. REDIRECT 5-3 Vibrational Mode of a Stretched String