# Difference between revisions of "Modeling activity sheet"

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− | The modeling activity sheet I used was adapted from a colleague's pre-algebra quiz about linear equations. Since she did not have a digital copy, I just made changes in class while going through the activity. On this page I have provided all of the questions | + | The modeling activity sheet I used was adapted from a colleague's pre-algebra quiz about linear equations. Since she did not have a digital copy, I just made changes in class while going through the activity. On this page I have provided all of the questions and solution methods. |

=== REASONING WITH TWO-STEP EQUATIONS === | === REASONING WITH TWO-STEP EQUATIONS === | ||

---- | ---- | ||

+ | Directions: Working with your partner, write equations using variables to describe the situations in each problem. <br/> | ||

+ | <br/> | ||

+ | |||

+ | 1. There are 8 presents on a table, and each present weighs the same amount. Combined, the presents weigh 24 pounds. How much does one present weigh? (Even if you can solve this without an algebraic phrase, use a variable to write an equation). <br/> <br/> | ||

+ | |||

+ | 2. 3 of the presents on the table are replaced by 3 books. Now the total weight is 42 pounds. How much does each book weigh? <br/> <br/> | ||

+ | |||

+ | 3. Jackie and Danny went shopping. Jackie bought 5 pens for $15, and Danny bought 2 pens and 6 toy cars for $48. <br/> | ||

+ | a) If each pen costs the same amount, how much does each pen cost? <br/> | ||

+ | b) How much does one toy car cost if they are all the same price? <br/> <br/> | ||

+ | |||

+ | 4. 7 pumpkins, each weighing the same, weigh 49 pounds total. 4 of these pumpkins, plus 8 starfish, weigh 52 pounds. Find the weight of 1 starfish. <br/> <br/> | ||

+ | |||

+ | 5. Create your own situation that can be modeled by an equation (make sure you can answer it!). Swap problems with another group and solve each other's situations. <br/> <br/> | ||

+ | |||

+ | === SOLUTIONS === | ||

+ | |||

+ | ---- | ||

+ | |||

+ | 1. Let p represent the weight of one present. Then 8p=24. When solved by dividing both sides by 8, we get p=3, so one present weighs one pound <br/> <br/> | ||

+ | |||

+ | |||

+ | 2. From the last question, we know that the 5 remaining presents weigh 3(5)=15 pounds. So if b represents the weight of one book, we now have the equation 3b+15=42. After subtracting 15 from both sides and dividing by 3, we get b=9, so one book weighs 9 pounds. <br/> <br/> | ||

+ | |||

+ | |||

+ | 3. a) If p represents the cost of one pen, then 5p=15. Solving this results in p=3, so one pen costs $3. <br/> | ||

+ | b) Using the information from part (a), Danny's 2 pens cost $6. So if c represents the cost of a car, then 6c+6=48. Solving this using subtraction and division, we get c=7, so each toy car costs $7. <br/> <br/> | ||

+ | |||

+ | |||

+ | 4. To figure out the weight of one pumpkin (represented by p), use the equation 7p=49. Solve this using division to get p=7, and so one pumpkin weighs 7 pounds. Use this information to figure out that 4 pumpkins weighs 7*4=28 pounds, so 4 pumpkins plus 8 starfish (where s represents the weight of one starfish), can be represented by 8s+28=52. Solve this by using subtraction and division to get s=3, so one starfish weighs 3 pounds.<br/> <br/> | ||

+ | |||

+ | [[Case Study of Models in Math Instruction | Back to main project page]] |

## Latest revision as of 20:34, 7 December 2011

The modeling activity sheet I used was adapted from a colleague's pre-algebra quiz about linear equations. Since she did not have a digital copy, I just made changes in class while going through the activity. On this page I have provided all of the questions and solution methods.

### REASONING WITH TWO-STEP EQUATIONS

Directions: Working with your partner, write equations using variables to describe the situations in each problem.

1. There are 8 presents on a table, and each present weighs the same amount. Combined, the presents weigh 24 pounds. How much does one present weigh? (Even if you can solve this without an algebraic phrase, use a variable to write an equation).

2. 3 of the presents on the table are replaced by 3 books. Now the total weight is 42 pounds. How much does each book weigh?

3. Jackie and Danny went shopping. Jackie bought 5 pens for $15, and Danny bought 2 pens and 6 toy cars for $48.

a) If each pen costs the same amount, how much does each pen cost?

b) How much does one toy car cost if they are all the same price?

4. 7 pumpkins, each weighing the same, weigh 49 pounds total. 4 of these pumpkins, plus 8 starfish, weigh 52 pounds. Find the weight of 1 starfish.

5. Create your own situation that can be modeled by an equation (make sure you can answer it!). Swap problems with another group and solve each other's situations.

### SOLUTIONS

1. Let p represent the weight of one present. Then 8p=24. When solved by dividing both sides by 8, we get p=3, so one present weighs one pound

2. From the last question, we know that the 5 remaining presents weigh 3(5)=15 pounds. So if b represents the weight of one book, we now have the equation 3b+15=42. After subtracting 15 from both sides and dividing by 3, we get b=9, so one book weighs 9 pounds.

3. a) If p represents the cost of one pen, then 5p=15. Solving this results in p=3, so one pen costs $3.

b) Using the information from part (a), Danny's 2 pens cost $6. So if c represents the cost of a car, then 6c+6=48. Solving this using subtraction and division, we get c=7, so each toy car costs $7.

4. To figure out the weight of one pumpkin (represented by p), use the equation 7p=49. Solve this using division to get p=7, and so one pumpkin weighs 7 pounds. Use this information to figure out that 4 pumpkins weighs 7*4=28 pounds, so 4 pumpkins plus 8 starfish (where s represents the weight of one starfish), can be represented by 8s+28=52. Solve this by using subtraction and division to get s=3, so one starfish weighs 3 pounds.